1-(10/x)+(21/x^2)=0

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Solution for 1-(10/x)+(21/x^2)=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

21/(x^2)-(10/x)+1 = 0

21/(x^2)-10*x^-1+1 = 0

21*x^-2-10*x^-1+1 = 0

t_1 = x^-1

21*t_1^2-10*t_1^1+1 = 0

21*t_1^2-10*t_1+1 = 0

DELTA = (-10)^2-(1*4*21)

DELTA = 16

DELTA > 0

t_1 = (16^(1/2)+10)/(2*21) or t_1 = (10-16^(1/2))/(2*21)

t_1 = 1/3 or t_1 = 1/7

t_1 = 1/7

x^-1-1/7 = 0

1*x^-1 = 1/7 // : 1

x^-1 = 1/7

-1 < 0

1/(x^1) = 1/7 // * x^1

1 = 1/7*x^1 // : 1/7

7 = x^1

x = 7

t_1 = 1/3

x^-1-1/3 = 0

1*x^-1 = 1/3 // : 1

x^-1 = 1/3

-1 < 0

1/(x^1) = 1/3 // * x^1

1 = 1/3*x^1 // : 1/3

3 = x^1

x = 3

x in { 7, 3 }

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